An Interesting Theorem: Proving 4 = 0

Theorem: The digit 4 is a constant number. But sometimes it is not so. It becomes equal to zero.

∴ To prove: 4 = 0

Proof:

Statement	Proof
Let we have an equation as follows
4² – 4² = 0	Universal truth as 16 – 16 = 0
it can be written
( 4 + 4 ) ( 4 - 4 ) = 0	by the formula
	a² – b² = ( a + b ) ( a – b )
4 – 4 = 0	dividing both sides by 4 + 4
or 2² – 2² = 0	Given
( 2 + 2 ) ( 2 – 2 ) = 0	by the formula
	a² – b² = ( a + b ) (a – b )
2 + 2 = 0	dividing both sides by 2 – 2
4 = 0	Hence proved.

Those who'd like to challange above theorem's approach, ever remember solving limit problems at the beginning of calculus?